Sum square difference

The sum of the squares of the first ten natural numbers is,
12 + 22 + ... + 102 = 385

The square of the sum of the first ten natural numbers is,
(1 + 2 + ... + 10)2 = 552 = 3025

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.
+/- Click and see the code that is about the article.

#include 

int main ()

{
 int counter,first,second=0,third=0,last,finally;
 
 for (counter=1;counter<=100;counter++)
 
 {
  first=counter*counter;
  second +=first;
 }
  printf("First : %d\n",second);

 for (counter=1;counter<=100;counter++)
 
 {
  third+=counter;
  last=third*third;
 }
  printf("Second : %d\n",last);
        finally=last-second;
  printf("Diffirence : %d\n",finally);

}